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# 2018 Neco Mathematics Objective and Theory Questions and Answers | Mathematics Neco Expo

2018 Neco Mathematics Objective and Theory Questions and Answers is available ,Mathematics 2018 Neco Exam Expo, all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers Neco maths portal

MATHS OBJ:
1-10: CDAAEABAEC
11-20: ACDDCDCDACu
31-40: CBEECCBDCC
41-50: DDCBCDDBBA
51-60: BCECCBBCEE

(1a)
Log10(20x - 10) - log10(x+3) = log10^5
Log10(20x-10/x+3)= log10^5
20x - 10/x + 3 = 5
Cross multiplying
20x - 10 = 5(x + 3)
5(4x - 2) = 5(x + 3)
4x - 2 = X + 3
4x - x = 3+2
3x = 5
X = 5/3 OR 1 whole no 2/3

(1b)
Let actual amount be #X
15% of #x = #600
15x/100 = 600
X = (100/15)*600
X = 100*40
X = 4,000
Actual amount = #4,000

(2a)
(X^2 Y^-3 Z)^3/4/X^-1 Y^4 Z^5
= (X^2)^3/4/X^-1 * (Y^-3)^3/4/Y^4 * Z^3/4/Z^5
= X^3/2/X^-1 * Y^-9/4/Y^4 * Z^3/4/Z^5
=X^3/2+1  * Y^-9/4-4 * Z^3/4-5
=X^5/2  * Y^-25/4 * Z^-17/4
=X^10/4 * Y^-25/4 * Z^-17/4

=(X^10/Y^25 Z^17)^1/4

(2b)
√2/k + √2 = 1/k - √2
Multiply both sides by (k+√2)(k-√2)
√2(k-√2) = k+√2
√2k-√2 = k+√2
√2k-k = 2+√2
K(√2 -1) = 2+√2
K = 2+√2/√2-1
K = -(2+√2)/1-√2
Rationalizing
K = -(2+√2) * 1+√2/1-√2
K = -(2+√2)(1+√2)/1 - 2
K = (2+√2)(1+√2)
K = 2+2√2 + √2+2
K = 4+3√2

(4)
Draw the diagram

(i) Arc length = Tita/360*2πr
= 72/360*2*22/7*14
=1/5*44*2
=88/5
=17.6cm

(ii) Perimeter of Sector = arc length +2r
=17.6+2(14)
=17.6+28
=45.6cm

(iii) Area of sector = Tita/360*πr²
=72/360*22/7*14/1*14/1
=1/5*22*2*14
=616/5
=123.2cm2

(5a)
Mode = mass with highest frequency = 35kg
Median is the 18th mass
= 40kg.

(5b)
In a tabular form

Under Masses(x kg)
30,35,40,45,50,55

Under frequency(f)
5,9,7,6,4,4
Ef = 35

Under X-A
-10, -5, 0, 5, 10, 15

Under F(X-A)
-50, -45, 0, 30, 40, 60
Ef(X - A) = 35

Mean = A + (Ef(X - A)/Ef)
= 40 + 35/35
= 40 + 1
= 41kg

( x=a+by(eqi)
when y=5 and x=19
19=a+5b(eqii)
when y=10 and x=34
34=a+10b(eqiii)
solving eqii and eqiii
a+10b=34
a+5b=19
=>5b=15
b=15/5=3
putting b=3 in eqii
19=a+5(3)
19=a+15
a=19-15
a=4

(8i)
Putting a=4 and b=3 in eqi
x=4+3y
This is the relationship between xand y

(8ii)
When y=7
x=4+3(7)
x=4+21
x=25

11a)
x+y/2 =11
x+y= 11*2
x+y= 22 ---(1)
x-y= 4 ----(11)
x+y = 22----(1)
-
x-y= 4----(11)
____________
2y = 18
y= 18/2
y=9
Substitute y=9 in equ 1
x+9=22
x=22-9
x=13
x=13, y=9
x+y= 13+9= 22
Sum of the two number

(11b)
(6x + 3) dx
(6x + 3)dx
(6x +3)^6 - (6x + 3)^1
(6 x + 3)^5
(7776x^5 + 243)
38,880x/6 + 243
6480 x^6 + 243x
9(720x^6 + 27x)

(11c)
y = x² + 5x - 3 (x = 2)
y = 2² + 5(2) - 3
y = 4 + 10 - 3
y = 14 - 3
y = 11
Gradient of the curve = 11

Monday 4th June 2018

OBJ � General Mathematics � 10:00am � 11:45am
Essay � General Mathematics � 12:00noon �2:30pm

Mathematics Neco exam will be deliver Night Before the exam day, we are not going to post answers here for free, Check our previous exam>>>  2018 Neco Geography Objective & Practical / Physical Questions and Answers | Geography Expo

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2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers

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Last edited by Emmi on Mon 4 Jun 2018 - 11:58; edited 6 times in total
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