MATHS OBJ:

1-10: DCBBDCCADB

11-20: ACBACCDADA

21-30: DAAAABDBBB

31-40: ABCDABCDCA

41-50: DBABCBABBB

*COMPLETED...!

1-10: DCBBDCCADB

11-20: ACBACCDADA

21-30: DAAAABDBBB

31-40: ABCDABCDCA

41-50: DBABCBABBB

*COMPLETED...!

ANSWER NUMBER 4

ANSWER NUMBER ONE(1)

ANSWER NUMBER 8

ANSWER NUMBER 7

ANSWER NUMBER

ANSWER NUMBER 6

(7a)

2

S(2x³ - 4x + 6)dx

1

= 2x³+¹/3+1 - 4x¹+¹/1+1 + 6x]2

1

=2x^4/4 - 4x²/2 +6x]2, 1

= x^4/2 - 2x² + 6x]2, 1

=(2^4/2 - 2(2²) + 6(2)) - (1^4/2 - 2(1)² + 6(1))

=(8 - 8 + 12) - (1/2 - 2 + 6)

=12 - 4½

= 7½

(7b)

Given; P^-1 = (-1 1)

(4 -3)

P = (p-1)^-1 = C^T/|p^-¹|

=(-3 -1)

(-4 -1)/3 - 4

=(-3 -1)

(-4 -1)/-1

=(3 1)

(4 1)

(6ai)

The profit y = X²/8 + 5x

y = GHc20,000.00

Hence 20,000 = X²/8 + 5x

160,000 = X² + 40x

X² + 40x - 160,000 = 0

Since X is in thousands

X² + 40x - 160 = 0

(6aii)

Using quadratic formula

X = -b±√b² - 4ac/2a

Where; a = 1, b = 40 & c = -160

X = -40±√40² - 4(1)(-160)/2(1)

X= -40 ±√1600 + 640/2

X = -40 ±√2240/2

X = -40 ± 47.32/2

X = -40±47.32/2

= 7.32/2

X = 3.66

X ≈ 4

(6b)

Draw the diagram

Using ΔTOP

tan 28 = H/OP

OP = H/tan28

Then for ΔROP

tantita = H/2/OP

OP = H/2/tantita

Hence H/tan 28 = H/2/tantita

tantita = H/2 × tan 28/H

tantita = tan28/2

Hence Tita = 28/2 = 14•

(4a)

(2y+x) + (6y-2x+1) + 4y = 28 ...(i)

6y-2x + 1 = 4y... (II)

2y+ x +6y - 2x + 1 +4 = 28

12y + x +6 -2x + 1 + 4 = 28

12y - x + 1 = 28

12y - x = 29... (III)

6y-2x + 1 = 4y, 6y-2x - 4y = 1

2y - 2x = -1... (iv)

24y - 2x = 54

2y - 2x = 1

22y/2w = 55/22 y = 2.5

12y - x = 27

12 (2.5) - x = 27

30 x 27 x=3

(b)

2y + x = 2 (2.5) + 3 = 5+3 = 8cm

6y - 2x + 1 = (2.5)-2 (3) + 1

= 15-6 + 1 = 10cm

4y = 4(2.5) = 10cm

Question 1

A = {2, 4, 6, 8}, B = {2, 3, 7, 9} and C = {x: 3 < x < 9} are subsets of the universal-set

U = {2, 3, 4, 5, 6, 7, 8, 9}. Find

(a) A n(B’nC’);

(b) (AuB) n(BuC).

Mathematics waec gce 2017 ObservationPlease ensure to use curly brackets to enclose the elements of the sets.

Furthermore always list the elements of set C hence, this is for you to be able to find its complement.

Do it this way C i.e. C = {4, 5,6, 7, 8}, obtain the compliments of the sets Band C thus B’ = {4,5,6, 8}, C’ = {2, 3, 9,}.

Using these sets, the following procedures were to be followed:

(a)(B’ nC’) = { } Hence An (B’ n C’) = { }. Don’t be like Some candidates know to write like this { 0 } instead of { } or 0.

(b) (A u B) = { 2, 3,4,6, 7, 8, 9 }, (BuC) = {2, 3, 4,5,6, 7, 8, 9 } Therefore { Au B } n (BuC) = { 2, 3, 4, 6, 7, 8, 9 }.

Question 2

(a) The angle of depression of a boat from the mid-point of a vertical cliff is 35°. If the boat is 120 m from the foot of the cliff, calculate the height of the cliff.

(b) Towns P and Q are x km apart. Two motorists set out at the same time from P to Q at steady speeds of 60 km/h and 80 km/h. The faster motorist got to Q 30 minutes earlier than the other. Find the value of x.

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