(1a)

DRAW A TABLE WITH THE FOLLOWING




Burette reading|ROUGH|1st  |2nd  |3rd 

Final          |13.60|15.50|14.80|12.50

Initial        |1.00 |3.10 |2.40 |0.00

Vol. acid used |12.60|12.60|12.40|12.50




Volume of S2O3²- =12.60+12.40+12.50/3

=37.50/3

=12.50cm³




(1bi) 

Conc. in g/dm³ = molar mass * conc in mol/dm³

But molar mass of Na2S2O3

=(23*2)+(32*2)+(16*3)

=46 + 64 + 48

=158g/mol

Therefore 15.8g/dm³ = 158g/mol * conc of A in mol/dm³




Conc of A in mol/dm³ = 15.8/158

=0.1mol/dm³




(1bii) 

Using CaVa/CbVb = na/nb

0.1*12.50/Cb * 25.00 = 2/1




50Cb = 1.25

Cb = 1.25/50

Cb = 0.025mol/dm³




The conc of I2 in B = 0.025mol/dm³




(1biii) 

Gram conc of I2 = molar mass * molar conc 

= (127*2)*0.025

=6.35g/dm³




Percentage mass of I2 in sample = 6.35/9.0 *100%

= 0.7056 * 100%

=70.56%




(1c) 

There have to be a change in the colour of the mixture before it is added. The end point is known when the blue colour formed as starch is added, changes to colourless







====================










(2a)

Test: C + Water and filtered

Observation: part of C dissolves, colour less filtrate is formed

Inference: C is a mixture of a soluble salt




(2bi)

Test: 2cm^2 of filterate of salt C + AgNO3(aq) then dilute HNO3

Observation: white precipitate is formed

Inference: Cl^- present 




(2bii)

Test: Solution im 2(b)(i) + excess NH3 solution

Observation: precipitate disorder in excess solution of NH3

Inference; Cl^- confirmed




(2ci)

Test: Resident + dilute HCl + shake 

Observation; residue dissolved to form a blue solution

Inference; Cu^2+ present




(2cii)

Test; solution in 2(c)(i) + NH3 solution in drops and then in excess.

Observation: light pale blue precipitate is formed precipitate dissolved in excess solution of NH3 to give a deep blue solution

Inference; Cu^2+ confirmed.




=====================







(3ai)

On adding BaCl2 solutions to a portion of saturated Na2CO3 precipitate is formed,precipitate dissolves on adding excess dilute HCl




(3aii)

Q is reducing agent like SO2, H2S, CO




(3bi)

calcium oxide(Cao)




(3bii)

concentrated H2SO4




(3c)

NaOH pellet is delinquescent because it absorb moisture from the atmosphere to form solution










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ALSO SEE: 2018 Waec Gce Physical and Practical Geography Questions and Answers | Waec Gce Expo

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